{"id":12367,"date":"2025-05-10T00:00:00","date_gmt":"2025-05-09T15:00:00","guid":{"rendered":"https:\/\/www.educational-lounge.com\/?p=12367"},"modified":"2025-05-09T12:46:24","modified_gmt":"2025-05-09T03:46:24","slug":"%e3%80%90%e6%95%b0%e5%ad%a6%e2%85%b2%e3%80%91%e6%a5%b5%e9%99%90%e8%a8%88%e7%ae%97%e3%81%ae%e5%8e%9f%e5%89%87%e7%a2%ba%e8%aa%8d%e3%81%a8%e7%9b%b4%e8%a6%b3%e7%9a%84%e3%81%aa%e7%90%86%e8%a7%a3%e3%82%92","status":"publish","type":"post","link":"https:\/\/www.educational-lounge.com\/?p=12367","title":{"rendered":"\u3010\u6570\u5b66\u2162\u3011\u6975\u9650\u8a08\u7b97\u306e\u539f\u5247\u78ba\u8a8d\u3068\u76f4\u89b3\u7684\u306a\u7406\u89e3\u3092\u3057\u3088\u3046\uff01"},"content":{"rendered":"

\u3069\u3046\u3082, \u307f\u306a\u3055\u3093\u3053\u3093\u306b\u3061\u306f\u3002\u9ad8\u6a4b\u4f73\u4f51\u3067\u3059\u3002
\n\u4eca\u56de\u306f\u6570\u5b66\u2162\u3067\u5b66\u7fd2\u3059\u308b\u6975\u9650\u306b\u3064\u3044\u3066\u304a\u8a71\u3057\u307e\u3059\u3002
\n\u6975\u9650\u3068\u3044\u3046\u5206\u91ce\u306f\u5927\u304d\u304f\u5206\u3051\u3066\u3001\u6570\u5217\u306e\u6975\u9650\u3001\u95a2\u6570\u306e\u6975\u9650\u306e2\u3064\u304c\u3042\u308a\u307e\u3059\u3002
\n\u3053\u308c\u3089\u306e\u6975\u9650\u8a08\u7b97\u306e\u539f\u5247\u3068\u3001\u76f4\u89b3\u7684\u306a\u30a4\u30e1\u30fc\u30b8\u304b\u3089\u7d50\u679c\u304c\u5f97\u3089\u308c\u308b\u5834\u5408\u304c\u3042\u308b\u3053\u3068\u3092\u3053\u3053\u3067\u7d39\u4ecb\u3057\u307e\u3057\u3087\u3046\u3002
\n\u306a\u304a, \u3053\u306e\u8a18\u4e8b\u5185\u3067$n$\u3092\u6b63\u306e\u6574\u6570\u3068\u3057\u307e\u3059\u3002<\/p>\n\n

\u221e\u306f\u3068\u3066\u3082\u5927\u304d\u3044\u3068\u3044\u3046\u610f\u5473\u306e\u8a18\u53f7<\/h2>\n

\"\"
\n$a_n=n$\u3067\u4e0e\u3048\u3089\u308c\u308b\u6570\u5217$\\{a_n\\}$\u306b\u3064\u3044\u3066\u8003\u3048\u3066\u307f\u307e\u3057\u3087\u3046\u3002
\n\u5177\u4f53\u7684\u306b\u6570\u5217\u306e\u9805\u3092\u66f8\u304d\u3060\u3059\u3068\u4e0b\u306e\u3088\u3046\u306b\u306a\u308a\u307e\u3059\u3002$$1, 2, 3, \\cdots\\cdots, 1000, \\cdots\\cdots, 100000, \\cdots\\cdots$$\u756a\u53f7$n$\u304c\u5927\u304d\u304f\u306a\u308c\u3070\u306a\u308b\u307b\u3069\u6570\u5217\u306e\u9805$a_n$\u306f\u969b\u9650\u306a\u304f\u5927\u304d\u304f\u306a\u308a\u307e\u3059\u3002<\/p>\n

\n
\n
\u3053\u306e\u3053\u3068\u3092, \u3068\u3066\u3082\u5927\u304d\u3044\u3053\u3068\u3092\u610f\u5473\u3059\u308b\u8a18\u53f7$\\infty$\u3092\u7528\u3044\u3066$$\\lim_{n\\to\\infty}a_n=\\lim_{n\\to\\infty}n=\\infty$$\u3068\u8868\u3057, $\\{a_n\\}$\u306f(\u6b63\u306e\u7121\u9650\u5927\u306b)\u767a\u6563\u3059\u308b\u3068\u3044\u3044\u307e\u3059\u3002<\/div>\n<\/div>\n<\/div>\n

\u95a2\u6570$f(x)=x$\u306b\u5bfe\u3057\u3066\u3082, $x$\u306e\u5024\u3092\u5927\u304d\u304f\u3059\u308c\u3070\u3059\u308b\u307b\u3069\u95a2\u6570\u5024$f(x)$\u306f\u969b\u9650\u306a\u304f\u5927\u304d\u304f\u306a\u308b\u304b\u3089
\n$$\\lim_{x\\to\\infty}f(x)=\\lim_{x\\to\\infty}x=\\infty$$\u3068\u8868\u3057, $f(x)$\u306f(\u6b63\u306e\u7121\u9650\u5927\u306b)\u767a\u6563\u3059\u308b\u3068\u3044\u3044\u307e\u3059\u3002<\/p>\n

\u540c\u69d8\u306b, $a_n=\\sqrt{n}$\u3084$a_n=n^2$\u306b\u5bfe\u3057\u3066, $$\\lim_{n\\to\\infty}a_n=\\infty$$\u3068\u306a\u308a, $f(x)=x^{\\frac{3}{2}}$, $f(x)=x^4$\u306b\u5bfe\u3057\u3066\u3082$$\\lim_{x\\to\\infty}f(x)=\\infty$$\u3068\u306a\u308a\u307e\u3059\u3002<\/p>\n

\n
\n
\u3057\u305f\u304c\u3063\u3066, $a_n=n^2+\\sqrt{n}$\u3084$f(x)=x^4+x^{\\frac{3}{2}}$\u306f, $n\\to\\infty$, $x\\to\\infty$\u3068\u3059\u308b\u3068$\\infty+\\infty$\u3059\u306a\u308f\u3061$\\infty$\u3068\u306a\u308a\u307e\u3059\u3002<\/div>\n<\/div>\n<\/div>\n

\u3055\u3089\u306b, $a_n=-n$\u3084$f(x)=-x$\u306e\u3068\u304d, $n$\u3084$x$\u3092\u5927\u304d\u304f\u3059\u308c\u3070\u3059\u308b\u307b\u3069$a_n$\u3084$f(x)$\u306e\u5024\u304c\u5c0f\u3055\u304f\u306a\u308b\u3053\u3068\u3092
\n$$\\lim_{n\\to\\infty}a_n=\\lim_{n\\to\\infty}(-n)=-\\infty$$$$\\lim_{x\\to\\infty}f(x)=\\lim_{x\\to\\infty}(-x)=-\\infty$$
\n\u3068\u8868\u3057, \u3053\u308c\u3092(\u8ca0\u306e\u7121\u9650\u5927\u306b)\u767a\u6563\u3059\u308b\u3068\u3044\u3044\u307e\u3059\u3002<\/p>\n

$\\displaystyle\\lim_{n\\to\\infty}\\cfrac{1}{n}$\u3084$\\displaystyle\\lim_{x\\to\\infty}\\cfrac{1}{x}$\u306f\u53ce\u675f\u3059\u308b<\/h3>\n

\u6570\u5217$\\{a_n\\}$\u3084\u95a2\u6570$f(x)$\u306b\u304a\u3044\u3066, \u6975\u9650\u3092\u8003\u3048\u305f\u3068\u304d\u306b\u7279\u5b9a\u306e\u5024\u306b\u8fd1\u3065\u3044\u3066\u3044\u304f\u3053\u3068\u3092, \u53ce\u675f\u3059\u308b\u3068\u3044\u3044\u305d\u306e\u5024\u3092\u6975\u9650\u5024\u3068\u3044\u3044\u307e\u3059\u3002<\/p>\n

\u4f8b\u3048\u3070, $a_n=\\cfrac{1}{n}$\u3067\u4e0e\u3048\u3089\u308c\u308b\u6570\u5217$\\{a_n\\}$\u306b\u3064\u3044\u3066\u8003\u3048\u3066\u307f\u307e\u3057\u3087\u3046\u3002
\n\u5177\u4f53\u7684\u306b\u6570\u5217\u306e\u9805\u3092\u66f8\u304d\u3060\u3059\u3068\u4e0b\u306e\u3088\u3046\u306b\u306a\u308a\u307e\u3059\u3002$$1, \\cfrac{1}{2}, \\cfrac{1}{3}, \\cdots\\cdots, \\cfrac{1}{1000}, \\cdots\\cdots, \\cfrac{1}{100000}, \\cdots\\cdots$$
\n\u756a\u53f7$n$\u304c\u5927\u304d\u304f\u306a\u308c\u3070\u306a\u308b\u307b\u3069\u6570\u5217\u306e\u9805$a_n$\u306f$0$\u306b\u8fd1\u3065\u304d\u307e\u3059\u3002<\/p>\n

\n
\n
\u3053\u306e\u3053\u3068\u3092$$\\lim_{n\\to\\infty}a_n=\\lim_{n\\to\\infty}\\cfrac{1}{n}=0$$\u3068\u8868\u3057, $\\{a_n\\}$\u306f$0$\u306b\u53ce\u675f\u3059\u308b\u3068\u3044\u3044\u307e\u3059\u3002<\/div>\n<\/div>\n<\/div>\n

\u95a2\u6570$f(x)=\\cfrac{1}{x}$\u306b\u5bfe\u3057\u3066\u3082, $x$\u306e\u5024\u3092\u5927\u304d\u304f\u3059\u308c\u3070\u3059\u308b\u307b\u3069\u95a2\u6570\u5024$f(x)$\u306f$0$\u306b\u8fd1\u3065\u304f\u304b\u3089
\n$$\\lim_{x\\to\\infty}f(x)=\\lim_{x\\to\\infty}\\cfrac{1}{x}=0$$\u3068\u8868\u3057, $f(x)$\u306f$0$\u306b\u53ce\u675f\u3059\u308b\u3068\u3044\u3044\u307e\u3059\u3002<\/p>\n

\n
\n
$\\displaystyle\\lim_{n\\to\\infty}\\cfrac{2}{n}$\u3084$\\displaystyle\\lim_{x\\to\\infty}\\left(-\\cfrac{3}{x}\\right)$\u3082$0$\u306b\u53ce\u675f\u3057\u307e\u3059\u3002<\/div>\n<\/div>\n<\/div>\n

\u3053\u308c\u3089\u3092\u4f7f\u3063\u3066\u3044\u308d\u3044\u308d\u306a\u6975\u9650\u3092\u8003\u3048\u3066\u307f\u307e\u3057\u3087\u3046\u3002<\/p>\n\n

\u6975\u9650\u8a08\u7b97\u306e\u539f\u5247\u306f\u53ce\u675f\u3059\u308b\u9805\u3092\u3064\u304f\u308b\u3053\u3068<\/h2>\n

\"\"
\n\u3053\u3053\u3067\u306f\u5177\u4f53\u7684\u306a\u6975\u9650\u8a08\u7b97\u3092\u3057\u3066\u307f\u307e\u3057\u3087\u3046\u3002<\/p>\n

\n
\u6975\u9650\u8a08\u7b97\u306e\u539f\u5247<\/div>\n
\n
\n
    \u307e\u305a\u306f$n\\to\\infty$\u3084$x\\to\\infty$\u3068\u3059\u308b\u3002\u6975\u9650\u304c\u5206\u304b\u3089\u306a\u3051\u308c\u3070,\u53ce\u675f\u3059\u308b\u9805\u3092\u3064\u304f\u308b\u3002\u4f8b\u3048\u3070, $\\cfrac{1}{\\infty}$\u3068\u306a\u308b\u90e8\u5206\u304c\u4f5c\u308c\u308c\u3070, \u305d\u308c\u3092$0$\u3068\u3057\u3066\u8a08\u7b97\u3059\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/ul>\n<\/div>\n<\/div>\n<\/div>\n

    $a_n=\\cfrac{6n-1}{2n+3}$\u3084$f(x)=\\cfrac{2-9x}{3x+4}$\u306b\u3064\u3044\u3066, $n$, $x$\u3092$\\infty$\u306b\u3057\u3066\u307f\u307e\u3057\u3087\u3046\u3002
    \n$n\\to\\infty$\u306e\u3068\u304d, $$6n-1\\to\\infty, 2n+3\\to\\infty$$\u3067\u3059\u304b\u3089$$\\lim_{n\\to\\infty}\\cfrac{6n-1}{2n+3}=\\cfrac{\\infty}{\\infty}$$\u3068\u306a\u308a\u307e\u3059\u3002
    \n$x\\to\\infty$\u306e\u3068\u304d, $$2-9x\\to-\\infty, 3n+4\\to\\infty$$\u3067\u3059\u304b\u3089$$\\lim_{n\\to\\infty}\\cfrac{2-9x}{3x+4}=\\cfrac{-\\infty}{\\infty}$$\u3068\u306a\u308a\u307e\u3059\u3002<\/p>\n

    \n
    \n
    $\\infty$\u306f\u3068\u3066\u3082\u5927\u304d\u3044\u3053\u3068\u3092\u8868\u3059\u8a18\u53f7\u306a\u306e\u3067\u7d04\u5206\u3067\u304d\u307e\u305b\u3093\u3002\u3053\u306e\u307e\u307e\u3067\u306f\u5024\u304c\u5b9a\u307e\u3089\u306a\u3044\u306e\u3067\u4e0d\u5b9a\u5f62\u3068\u547c\u3070\u308c\u307e\u3059\u3002<\/div>\n<\/div>\n<\/div>\n

    \u3053\u306e\u3088\u3046\u306a\u5206\u6570\u5f0f\u306e\u5834\u5408, \u5206\u6bcd\u306e\u6700\u9ad8\u6b21\u6570\u306b\u6ce8\u76ee\u3057\u307e\u3057\u3087\u3046\u3002<\/p>\n

    \u4eca\u56de\u306f\u3068\u3082\u306b\u5206\u6bcd\u306f$1$\u6b21\u5f0f\u306b\u306a\u3063\u3066\u3044\u307e\u3059\u3002\u3053\u306e\u3068\u304d\u5206\u6bcd\u3068\u5206\u5b50\u306b$\\cfrac{1}{n}$, $\\cfrac{1}{x}$\u3092\u304b\u3051\u307e\u3059\u3002<\/p>\n

    \u3064\u307e\u308a,$$a_n=\\cfrac{6n-1}{2n+3}=\\cfrac{(6n-1)\\times\\cfrac{1}{n}}{(2n+3)\\times\\cfrac{1}{n}}=\\cfrac{6-\\cfrac{1}{n}}{2+\\cfrac{3}{n}}$$$$f(x)=\\cfrac{(2-9x)\\times\\cfrac{1}{x}}{(3x+4)\\times\\cfrac{1}{x}}=\\cfrac{\\cfrac{2}{x}-9}{3+\\cfrac{4}{x}}$$
    \n\u3068\u3057\u307e\u3059\u3002\u3053\u308c\u3067, $\\cfrac{1}{\\infty}$\u3068\u306a\u308b\u90e8\u5206\u304c\u4f5c\u308c\u307e\u3057\u305f\u3002\u3088\u3063\u3066, $$\\lim_{n\\to\\infty}a_n=\\cfrac{6-\\cfrac{1}{n}}{2+\\cfrac{3}{n}}=\\cfrac{6-0}{2+0}=3$$$$\\lim_{x\\to\\infty}f(x)=\\cfrac{\\cfrac{2}{x}-9}{3+\\cfrac{4}{x}}=\\cfrac{0-9}{3+0}=-3$$
    \n\u3068\u306a\u308a, \u3068\u3082\u306b\u53ce\u675f\u3059\u308b\u3053\u3068\u304c\u5206\u304b\u308a\u307e\u3057\u305f\u3002<\/p>\n

    \u6b21\u306b, $a_n=\\cfrac{n+1}{n^2+n+1}$\u3084$f(x)=\\cfrac{x^3+x+1}{2x^2+x+2}$\u306b\u3064\u3044\u3066\u8003\u3048\u3066\u307f\u307e\u3057\u3087\u3046\u3002<\/p>\n

    \u5206\u6bcd\u306e\u6700\u9ad8\u6b21\u6570\u306f\u3068\u3082\u306b$2$\u3067\u3059\u304b\u3089, \u5206\u6bcd\u3068\u5206\u5b50\u306b$\\cfrac{1}{n^2}$, $\\cfrac{1}{x^2}$\u3092\u304b\u3051\u307e\u3059\u3002<\/p>\n

    \u3064\u307e\u308a,<\/p>\n

    $$a_n=\\cfrac{n+1}{n^2+n+1}=\\cfrac{(n+1)\\times\\cfrac{1}{n^2}}{(n^2+n+1)\\times\\cfrac{1}{n^2}}=\\cfrac{\\cfrac{1}{n}+\\cfrac{1}{n^2}}{1+\\cfrac{1}{n}+\\cfrac{1}{n^2}}$$
    \n$$f(x)=\\cfrac{(x^3+x+1)\\times\\cfrac{1}{x^2}}{(2x^2+x+2)\\times\\cfrac{1}{x^2}}=\\cfrac{x+\\cfrac{1}{x}+\\cfrac{1}{x^2}}{2+\\cfrac{1}{x}+\\cfrac{2}{x^2}}$$<\/p>\n

    \u3068\u3057\u307e\u3059\u3002\u3053\u308c\u3067, $\\cfrac{1}{\\infty}$\u3068\u306a\u308b\u90e8\u5206\u304c\u4f5c\u308c\u307e\u3057\u305f\u3002<\/p>\n

    \u3088\u3063\u3066,<\/p>\n

    $$\\lim_{n\\to\\infty}a_n=\\lim_{n\\to\\infty}\\cfrac{\\cfrac{1}{n}+\\cfrac{1}{n^2}}{1+\\cfrac{1}{n}+\\cfrac{1}{n^2}}=\\cfrac{0}{1}=0$$<\/p>\n

    \u3068\u306a\u308a\u307e\u3059\u3002\u307e\u305f, $f(x)$\u306b\u3064\u3044\u3066\u306f$x\\to\\infty$\u306e\u3068\u304d$\\cfrac{\\infty}{2}$\u3068\u306a\u308a, \u3053\u308c\u306f$\\infty$\u3067\u3059\u304b\u3089<\/p>\n

    $$\\lim_{x\\to\\infty}f(x)=\\lim_{x\\to\\infty}\\cfrac{x+\\cfrac{2}{x}+\\cfrac{2}{x^2}}{2+\\cfrac{1}{x}+\\cfrac{2}{x^2}}=\\infty$$
    \n\u3068\u306a\u308a\u307e\u3059\u3002<\/p>\n

    \u4ee5\u4e0a\u306e\u3088\u3046\u306b\u6975\u9650\u8a08\u7b97\u306e\u539f\u5247\u306f, \u53ce\u675f\u3059\u308b\u9805\u3092\u4f5c\u308b\u3053\u3068\u3067\u3059\u3002<\/p>\n\n

    \u9ad8\u6b21\u6570\u306e\u9805\u3092\u512a\u5148\u3057\u3066\u76f4\u89b3\u7684\u306b\u6975\u9650\u8a08\u7b97\u3059\u308b<\/h2>\n

    \"\"
    \n$n\\to\\infty$\u306e\u3068\u304d, $n$\u3082$n^2$\u3082$\\infty$\u306b\u767a\u6563\u3057\u307e\u3059\u304c, \u76f4\u89b3\u7684\u306b\u3082$n^2$\u306e\u65b9\u304c$n$\u3088\u308a\u3082\u5927\u304d\u3044\u306e\u306f\u5206\u304b\u308b\u3067\u3057\u3087\u3046\u304b\u3002<\/p>\n

    \n
    \n
    $n$\u304c$1$\u5104\u306e\u3068\u304d, $n^2$\u306f$1$\u5104\u306e$2$\u4e57\u3068\u306a\u308a, $n$\u3082\u78ba\u304b\u306b\u5927\u304d\u3044\u3067\u3059\u304c$n^2$\u3068\u6bd4\u3079\u308b\u3068\u307e\u3060\u307e\u3060\u5c0f\u3055\u3044\u3067\u3059\u3002\u3057\u305f\u304c\u3063\u3066, $n$\u306f$n^2$\u3068\u6bd4\u3079\u305f\u3068\u304d\u7121\u8996\u3067\u304d\u308b\u57c3\u306e\u3088\u3046\u306a\u5b58\u5728\u3068\u898b\u306a\u305b\u307e\u3059\u3002<\/div>\n<\/div>\n<\/div>\n

    \u3053\u306e\u76f4\u89b3\u7684\u306a\u30a4\u30e1\u30fc\u30b8\u3092\u5229\u7528\u3057\u3066\u6975\u9650\u8a08\u7b97\u3092\u3057\u3066\u307f\u307e\u3059\u3002
    \n\u4f8b\u3048\u3070$n^2+n$\u306e\u6975\u9650\u3092\u8003\u3048\u308b\u3068\u304d\u306f$n^2+$(\u57c3)\u3068\u8003\u3048\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/p>\n

    \u4ee5\u4e0b, (\u57c3)\u3092$\\cdots\\cdots$\u3068\u8868\u3059\u3053\u3068\u306b\u3059\u308c\u3070,<\/p>\n

    $a_n=\\cfrac{6n-1}{2n+3}$\u3084$f(x)=\\cfrac{2-9x}{3x+4}$\u306f<\/p>\n

    $$\\lim_{n\\to\\infty}\\cfrac{6n-1}{2n+3}=\\lim_{n\\to\\infty}\\cfrac{6n\\cdots\\cdots}{2n\\cdots\\cdots}$$$$\\lim_{n\\to\\infty}\\cfrac{2-9x}{3x+4}=\\lim_{n\\to\\infty}\\cfrac{\\cdots\\cdots-9x}{3x\\cdots\\cdots}$$\u3068\u306a\u308a\u307e\u3059\u3002\u3059\u308b\u3068\u6975\u9650\u306f, \u7d04\u5206\u3057\u3066$$\\lim_{n\\to\\infty}\\cfrac{6n\\cdots\\cdots}{2n\\cdots\\cdots}=\\lim_{n\\to\\infty}\\cfrac{6\\cdots\\cdots}{2\\cdots\\cdots}=3$$$$\\lim_{x\\to\\infty}\\cfrac{\\cdots\\cdots-9x}{3x\\cdots\\cdots}=\\lim_{x\\to\\infty}\\cfrac{\\cdots\\cdots-9}{3\\cdots\\cdots}=-3$$\u3068\u306a\u308a\u307e\u3059\u3002<\/p>\n

    $a_n=\\cfrac{n+1}{n^2+n+1}$\u3084$f(x)=\\cfrac{x^3+x+1}{2x^2+x+2}$\u306b\u3064\u3044\u3066\u306f,<\/p>\n

    \u5206\u6bcd\u306f\u5206\u6bcd, \u5206\u5b50\u306f\u5206\u5b50\u3067\u540c\u69d8\u306b\u8003\u3048\u308c\u3070,$$\\lim_{n\\to\\infty}\\cfrac{n+1}{n^2+n+1}=\\lim_{n\\to\\infty}\\cfrac{n\\cdots\\cdots}{n^2\\cdots\\cdots}=\\lim_{n\\to\\infty}\\cfrac{1\\cdots\\cdots}{n\\cdots\\cdots}=0$$$$\\lim_{x\\to\\infty}\\cfrac{x^3+x+1}{2x^2+x+2}=\\lim_{x\\to\\infty}\\cfrac{x^3\\cdots\\cdots}{2x^2\\cdots\\cdots}=\\lim_{x\\to\\infty}\\cfrac{x\\cdots\\cdots}{2\\cdots\\cdots}=\\infty$$\u3068\u306a\u308a\u307e\u3059\u3002<\/p>\n

    \u6839\u53f7\u3092\u542b\u3093\u3060\u5f0f\u3084\u5206\u6570\u5834\u3082\u540c\u69d8\u306b\u8003\u3048\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002\u4f8b\u3048\u3070$\\sqrt{4n^2-n}$\u306f$n$\u304c\u5341\u5206\u5927\u304d\u3044\u3068\u304d, $$\\sqrt{4n^2-n}=\\sqrt{4n^2\\cdots\\cdots}=2n\\cdots\\cdots$$\u306e\u3088\u3046\u306b$1$\u6b21\u5f0f\u3068\u898b\u306a\u305b\u307e\u3059\u3002\u3057\u305f\u304c\u3063\u3066, $\\displaystyle\\lim_{n\\to\\infty}\\cfrac{8n}{\\sqrt{4n^2-n}+2n}$\u306f$$\\displaystyle\\lim_{n\\to\\infty}\\cfrac{8n}{\\sqrt{4n^2-n}+2n}=\\lim_{n\\to\\infty}\\cfrac{8n}{2n\\cdots\\cdots+2n}=\\lim_{n\\to\\infty}\\cfrac{8}{2\\cdots\\cdots+2}=2$$\u3068\u8a08\u7b97\u3067\u304d\u307e\u3059\u3002<\/p>\n

    \n
    \n
    \u3053\u306e\u3088\u3046\u306b\u6700\u9ad8\u6b21\u6570\u306e\u4fc2\u6570\u306b\u6ce8\u76ee\u3057\u3066\u6975\u9650\u8a08\u7b97\u3059\u308b\u3053\u3068\u304c\u3067\u304d\u307e\u3059\u3002<\/div>\n<\/div>\n<\/div>\n\n

    \u304a\u308f\u308a\u306b<\/h2>\n

    \u4eca\u56de\u306f\u6570\u5b66\u2162\u3067\u5b66\u7fd2\u3059\u308b\u6975\u9650\u306b\u3064\u3044\u3066\u304a\u8a71\u3057\u307e\u3057\u305f\u3002\u4e0a\u3067\u7d39\u4ecb\u3057\u305f\u3082\u306e\u4ee5\u5916\u306b\u3082\u4e0d\u5b9a\u5f62\u306e\u89e3\u6d88\u65b9\u6cd5\u3084, \u53ce\u675f\u3059\u308b\u6975\u9650\u306e\u516c\u5f0f\u304c\u3042\u308a\u307e\u3059\u3002
    \n\u3069\u3093\u306a\u5834\u5408\u3067\u3042\u3063\u3066\u3082\u53ce\u675f\u3059\u308b\u9805\u3092\u3064\u304f\u308b\u3068\u3044\u3046\u539f\u5247\u306f\u5fd8\u308c\u3066\u306f\u3044\u3051\u307e\u305b\u3093\u3002<\/p>\n

    \u95a2\u6570\u306e\u6975\u9650\u5024\u3092\u8a08\u7b97\u3067\u304d\u308b\u3088\u3046\u306b\u306a\u308b\u3068\u3001\u3042\u3089\u3086\u308b\u95a2\u6570\u306e\u5c0e\u95a2\u6570\u3092\u6c42\u3081\u308b\u3053\u3068\u304c\u3067\u304d\u308b\u3088\u3046\u306b\u306a\u308b\u305f\u3081\u3001\u5fae\u5206\u6cd5\u306b\u8a71\u304c\u9032\u3093\u3067\u3044\u304d\u307e\u3059\u3002\u6975\u9650\u306f\u5fae\u7a4d\u5206\u5b66\u306e\u5165\u308a\u53e3\u306b\u3042\u308a\u307e\u3059\u3002\u662f\u975e, \u3044\u308d\u3044\u308d\u306a\u6975\u9650\u3092\u8a08\u7b97\u3057\u3066\u307f\u3066\u4e0b\u3055\u3044\u3002<\/p>\n

    \u305d\u308c\u3067\u306f, \u4eca\u56de\u306f\u3053\u306e\u8fba\u3067\uff01<\/p>\n